Solve for x 2-(7x+5)=13-3x

$2 - (7 x + 5) = 13 - 3 x$

Step 1

Simplify $2 - (7 x + 5)$ .

Simplify each term.

Apply the distributive property.

$2 - (7 x) - 1 \cdot 5 = 13 - 3 x$

Multiply $7$ by $- 1$ .

$2 - 7 x - 1 \cdot 5 = 13 - 3 x$

Multiply $- 1$ by $5$ .

$2 - 7 x - 5 = 13 - 3 x$

Subtract $5$ from $2$ .

$- 7 x - 3 = 13 - 3 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$- 7 x - 3 + 3 x = 13$

Add $- 7 x$ and $3 x$ .

$- 4 x - 3 = 13$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- 4 x = 13 + 3$

Add $13$ and $3$ .

$- 4 x = 16$

Step 4

Divide each term in $- 4 x = 16$ by $- 4$ and simplify.

Divide each term in $- 4 x = 16$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{16}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{16}{- 4}$

Divide $x$ by $1$ .

$x = \frac{16}{- 4}$

Simplify the right side.

Divide $16$ by $- 4$ .

$x = - 4$