Solve for x 2 log of x+1=5

$2 \log (x + 1) = 5$

Step 1

Divide each term in $2 \log (x + 1) = 5$ by $2$ and simplify.

Divide each term in $2 \log (x + 1) = 5$ by $2$ .

$\frac{2 \log (x + 1)}{2} = \frac{5}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \log (x + 1)}{2} = \frac{5}{2}$

Divide $\log (x + 1)$ by $1$ .

$\log (x + 1) = \frac{5}{2}$

Step 2

Rewrite $\log (x + 1) = \frac{5}{2}$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{\frac{5}{2}} = x + 1$

Step 3

Solve for $x$ .

Rewrite the equation as $x + 1 = 10^{\frac{5}{2}}$ .

$x + 1 = 10^{\frac{5}{2}}$

Subtract $1$ from both sides of the equation.

$x = 10^{\frac{5}{2}} - 1$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = 10^{\frac{5}{2}} - 1$

Decimal Form:

$x = 315.22776601 \dots$

Solve for x 2 log of x+1=5

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