Solve for x 2(x^2-4x)-5=2x^2-6x+9

$2 (x^{2} - 4 x) - 5 = 2 x^{2} - 6 x + 9$

Simplify each term.

Apply the distributive property.

$2 x^{2} + 2 (- 4 x) - 5 = 2 x^{2} - 6 x + 9$

Multiply $- 4$ by $2$ .

$2 x^{2} - 8 x - 5 = 2 x^{2} - 6 x + 9$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x^{2}$ from both sides of the equation.

$2 x^{2} - 8 x - 5 - 2 x^{2} = - 6 x + 9$

Add $6 x$ to both sides of the equation.

$2 x^{2} - 8 x - 5 - 2 x^{2} + 6 x = 9$

Combine the opposite terms in $2 x^{2} - 8 x - 5 - 2 x^{2} + 6 x$ .

Subtract $2 x^{2}$ from $2 x^{2}$ .

$- 8 x - 5 + 0 + 6 x = 9$

Add $- 8 x - 5$ and $0$ .

$- 8 x - 5 + 6 x = 9$

Add $- 8 x$ and $6 x$ .

$- 2 x - 5 = 9$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$- 2 x = 9 + 5$

Add $9$ and $5$ .

$- 2 x = 14$

Divide each term in $- 2 x = 14$ by $- 2$ and simplify.

Divide each term in $- 2 x = 14$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{14}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{14}{- 2}$

Divide $x$ by $1$ .

$x = \frac{14}{- 2}$

Simplify the right side.

Divide $14$ by $- 2$ .

$x = - 7$