Solve for x 2^(x+3)-3=5

$2^{x + 3} - 3 = 5$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$2^{x + 3} = 5 + 3$

Add $5$ and $3$ .

$2^{x + 3} = 8$

Step 2

Create equivalent expressions in the equation that all have equal bases.

$2^{x + 3} = 2^{3}$

Step 3

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 3 = 3$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$x = 3 - 3$

Subtract $3$ from $3$ .

$x = 0$