Solve for x 2(x-3)+3=6x-5

$2 (x - 3) + 3 = 6 x - 5$

Step 1

Simplify $2 (x - 3) + 3$ .

Simplify each term.

Apply the distributive property.

$2 x + 2 \cdot - 3 + 3 = 6 x - 5$

Multiply $2$ by $- 3$ .

$2 x - 6 + 3 = 6 x - 5$

Add $- 6$ and $3$ .

$2 x - 3 = 6 x - 5$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$2 x - 3 - 6 x = - 5$

Subtract $6 x$ from $2 x$ .

$- 4 x - 3 = - 5$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- 4 x = - 5 + 3$

Add $- 5$ and $3$ .

$- 4 x = - 2$

Step 4

Divide each term in $- 4 x = - 2$ by $- 4$ and simplify.

Divide each term in $- 4 x = - 2$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{- 2}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{- 2}{- 4}$

Divide $x$ by $1$ .

$x = \frac{- 2}{- 4}$

Simplify the right side.

Cancel the common factor of $- 2$ and $- 4$ .

Factor $- 2$ out of $- 2$ .

$x = \frac{- 2 (1)}{- 4}$

Cancel the common factors.

Factor $- 2$ out of $- 4$ .

$x = \frac{- 2 \cdot 1}{- 2 \cdot 2}$

Cancel the common factor.

$x = \frac{- 2 \cdot 1}{- 2 \cdot 2}$

Rewrite the expression.

$x = \frac{1}{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}$

Decimal Form:

$x = 0.5$

Solve for x 2(x-3)+3=6x-5

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