Solve for x 2/(x+3)=(5-x)/(x+3)

$\frac{2}{x + 3} = \frac{5 - x}{x + 3}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$2 = 5 - x$

Rewrite the equation as $5 - x = 2$ .

$5 - x = 2$

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- x = 2 - 5$

Subtract $5$ from $2$ .

$- x = - 3$

Divide each term in $- x = - 3$ by $- 1$ and simplify.

Divide each term in $- x = - 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x = 3$