Solve for x 2(x-3)=(x-1)+7

$2 (x - 3) = (x - 1) + 7$

Step 1

Simplify $2 (x - 3)$ .

Rewrite.

$0 + 0 + 2 (x - 3) = x - 1 + 7$

Simplify by adding zeros.

$2 (x - 3) = x - 1 + 7$

Apply the distributive property.

$2 x + 2 \cdot - 3 = x - 1 + 7$

Multiply $2$ by $- 3$ .

$2 x - 6 = x - 1 + 7$

Step 2

Add $- 1$ and $7$ .

$2 x - 6 = x + 6$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$2 x - 6 - x = 6$

Subtract $x$ from $2 x$ .

$x - 6 = 6$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $6$ to both sides of the equation.

$x = 6 + 6$

Add $6$ and $6$ .

$x = 12$