Solve for x 2(x+4)-8=3x+10-4

$2 (x + 4) - 8 = 3 x + 10 - 4$

Step 1

Simplify $2 (x + 4) - 8$ .

Simplify each term.

Apply the distributive property.

$2 x + 2 \cdot 4 - 8 = 3 x + 10 - 4$

Multiply $2$ by $4$ .

$2 x + 8 - 8 = 3 x + 10 - 4$

Combine the opposite terms in $2 x + 8 - 8$ .

Subtract $8$ from $8$ .

$2 x + 0 = 3 x + 10 - 4$

Add $2 x$ and $0$ .

$2 x = 3 x + 10 - 4$

Step 2

Subtract $4$ from $10$ .

$2 x = 3 x + 6$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$2 x - 3 x = 6$

Subtract $3 x$ from $2 x$ .

$- x = 6$

Step 4

Divide each term in $- x = 6$ by $- 1$ and simplify.

Divide each term in $- x = 6$ by $- 1$ .

$\frac{- x}{- 1} = \frac{6}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{6}{- 1}$

Divide $x$ by $1$ .

$x = \frac{6}{- 1}$

Simplify the right side.

Divide $6$ by $- 1$ .

$x = - 6$