Solve for x 2(x-5)+3x=20

$2 (x - 5) + 3 x = 20$

Step 1

Simplify $2 (x - 5) + 3 x$ .

Simplify each term.

Apply the distributive property.

$2 x + 2 \cdot - 5 + 3 x = 20$

Multiply $2$ by $- 5$ .

$2 x - 10 + 3 x = 20$

Add $2 x$ and $3 x$ .

$5 x - 10 = 20$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$5 x = 20 + 10$

Add $20$ and $10$ .

$5 x = 30$

Step 3

Divide each term in $5 x = 30$ by $5$ and simplify.

Divide each term in $5 x = 30$ by $5$ .

$\frac{5 x}{5} = \frac{30}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{30}{5}$

Divide $x$ by $1$ .

$x = \frac{30}{5}$

Simplify the right side.

Divide $30$ by $5$ .

$x = 6$