Solve for X 20^2+15^2=X^2

$20^{2} + 15^{2} = X^{2}$

Step 1

Rewrite the equation as $X^{2} = 20^{2} + 15^{2}$ .

$X^{2} = 20^{2} + 15^{2}$

Step 2

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$X = \pm \sqrt{20^{2} + 15^{2}}$

Step 3

Simplify $\pm \sqrt{20^{2} + 15^{2}}$ .

Raise $20$ to the power of $2$ .

$X = \pm \sqrt{400 + 15^{2}}$

Raise $15$ to the power of $2$ .

$X = \pm \sqrt{400 + 225}$

Add $400$ and $225$ .

$X = \pm \sqrt{625}$

Rewrite $625$ as $25^{2}$ .

$X = \pm \sqrt{25^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$X = \pm 25$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$X = 25$

Next, use the negative value of the $\pm$ to find the second solution.

$X = - 25$

The complete solution is the result of both the positive and negative portions of the solution.

$X = 25, - 25$