Solve for x 20=5(-3+x)

$20 = 5 (- 3 + x)$

Step 1

Rewrite the equation as $5 (- 3 + x) = 20$ .

$5 (- 3 + x) = 20$

Step 2

Divide each term in $5 (- 3 + x) = 20$ by $5$ and simplify.

Divide each term in $5 (- 3 + x) = 20$ by $5$ .

$\frac{5 (- 3 + x)}{5} = \frac{20}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 (- 3 + x)}{5} = \frac{20}{5}$

Divide $- 3 + x$ by $1$ .

$- 3 + x = \frac{20}{5}$

Simplify the right side.

Divide $20$ by $5$ .

$- 3 + x = 4$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$x = 4 + 3$

Add $4$ and $3$ .

$x = 7$