Solve for x 24=4(6b-2x)

$24 = 4 (6 b - 2 x)$

Rewrite the equation as $4 (6 b - 2 x) = 24$ .

$4 (6 b - 2 x) = 24$

Divide each term in $4 (6 b - 2 x) = 24$ by $4$ and simplify.

Divide each term in $4 (6 b - 2 x) = 24$ by $4$ .

$\frac{4 (6 b - 2 x)}{4} = \frac{24}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (6 b - 2 x)}{4} = \frac{24}{4}$

Divide $6 b - 2 x$ by $1$ .

$6 b - 2 x = \frac{24}{4}$

Simplify the right side.

Divide $24$ by $4$ .

$6 b - 2 x = 6$

Subtract $6 b$ from both sides of the equation.

$- 2 x = 6 - 6 b$

Divide each term in $- 2 x = 6 - 6 b$ by $- 2$ and simplify.

Divide each term in $- 2 x = 6 - 6 b$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{6}{- 2} + \frac{- 6 b}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{6}{- 2} + \frac{- 6 b}{- 2}$

Divide $x$ by $1$ .

$x = \frac{6}{- 2} + \frac{- 6 b}{- 2}$

Simplify the right side.

Simplify each term.

Divide $6$ by $- 2$ .

$x = - 3 + \frac{- 6 b}{- 2}$

Cancel the common factor of $- 6$ and $- 2$ .

Factor $- 2$ out of $- 6 b$ .

$x = - 3 + \frac{- 2 (3 b)}{- 2}$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$x = - 3 + \frac{- 2 (3 b)}{- 2 (1)}$

Cancel the common factor.

$x = - 3 + \frac{- 2 (3 b)}{- 2 \cdot 1}$

Rewrite the expression.

$x = - 3 + \frac{3 b}{1}$

Divide $3 b$ by $1$ .

$x = - 3 + 3 b$