Solve for x 24=6(-x-3)

$24 = 6 (- x - 3)$

Step 1

Rewrite the equation as $6 (- x - 3) = 24$ .

$6 (- x - 3) = 24$

Step 2

Divide each term in $6 (- x - 3) = 24$ by $6$ and simplify.

Divide each term in $6 (- x - 3) = 24$ by $6$ .

$\frac{6 (- x - 3)}{6} = \frac{24}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 (- x - 3)}{6} = \frac{24}{6}$

Divide $- x - 3$ by $1$ .

$- x - 3 = \frac{24}{6}$

Simplify the right side.

Divide $24$ by $6$ .

$- x - 3 = 4$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- x = 4 + 3$

Add $4$ and $3$ .

$- x = 7$

Step 4

Divide each term in $- x = 7$ by $- 1$ and simplify.

Divide each term in $- x = 7$ by $- 1$ .

$\frac{- x}{- 1} = \frac{7}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{7}{- 1}$

Divide $x$ by $1$ .

$x = \frac{7}{- 1}$

Simplify the right side.

Divide $7$ by $- 1$ .

$x = - 7$