Solve for x 25x+12y+4<=130

$25 x + 12 y + 4 \leq 130$

Step 1

Move all terms not containing $x$ to the right side of the inequality.

Subtract $12 y$ from both sides of the inequality.

$25 x + 4 \leq 130 - 12 y$

Subtract $4$ from both sides of the inequality.

$25 x \leq 130 - 12 y - 4$

Subtract $4$ from $130$ .

$25 x \leq - 12 y + 126$

Step 2

Divide each term in $25 x \leq - 12 y + 126$ by $25$ and simplify.

Divide each term in $25 x \leq - 12 y + 126$ by $25$ .

$\frac{25 x}{25} \leq \frac{- 12 y}{25} + \frac{126}{25}$

Simplify the left side.

Cancel the common factor of $25$ .

Cancel the common factor.

$\frac{25 x}{25} \leq \frac{- 12 y}{25} + \frac{126}{25}$

Divide $x$ by $1$ .

$x \leq \frac{- 12 y}{25} + \frac{126}{25}$

Simplify the right side.

Move the negative in front of the fraction.

$x \leq - \frac{12 y}{25} + \frac{126}{25}$