Solve for x 27<=7x+6

$27 \leq 7 x + 6$

Step 1

Rewrite so $x$ is on the left side of the inequality.

$7 x + 6 \geq 27$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $6$ from both sides of the inequality.

$7 x \geq 27 - 6$

Subtract $6$ from $27$ .

$7 x \geq 21$

Step 3

Divide each term in $7 x \geq 21$ by $7$ and simplify.

Divide each term in $7 x \geq 21$ by $7$ .

$\frac{7 x}{7} \geq \frac{21}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} \geq \frac{21}{7}$

Divide $x$ by $1$ .

$x \geq \frac{21}{7}$

Simplify the right side.

Divide $21$ by $7$ .

$x \geq 3$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq 3$

Interval Notation:

$[3, \infty)$