Solve for x 28-5=2+3(x+3)

$28 - 5 = 2 + 3 (x + 3)$

Rewrite the equation as $2 + 3 (x + 3) = 28 - 5$ .

$2 + 3 (x + 3) = 28 - 5$

Simplify $2 + 3 (x + 3)$ .

Simplify each term.

Apply the distributive property.

$2 + 3 x + 3 \cdot 3 = 28 - 5$

Multiply $3$ by $3$ .

$2 + 3 x + 9 = 28 - 5$

Add $2$ and $9$ .

$3 x + 11 = 28 - 5$

Subtract $5$ from $28$ .

$3 x + 11 = 23$

Move all terms not containing $x$ to the right side of the equation.

Subtract $11$ from both sides of the equation.

$3 x = 23 - 11$

Subtract $11$ from $23$ .

$3 x = 12$

Divide each term in $3 x = 12$ by $3$ and simplify.

Divide each term in $3 x = 12$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$x = 4$