Solve for x 2sin(pi/4-x)+ square root of 3=0

$2 \sin (\frac{π}{4} - x) + \sqrt{3} = 0$

Step 1

Subtract $\sqrt{3}$ from both sides of the equation.

$2 \sin (\frac{π}{4} - x) = - \sqrt{3}$

Step 2

Divide each term in $2 \sin (\frac{π}{4} - x) = - \sqrt{3}$ by $2$ and simplify.

Divide each term in $2 \sin (\frac{π}{4} - x) = - \sqrt{3}$ by $2$ .

$\frac{2 \sin (\frac{π}{4} - x)}{2} = \frac{- \sqrt{3}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sin (\frac{π}{4} - x)}{2} = \frac{- \sqrt{3}}{2}$

Divide $\sin (\frac{π}{4} - x)$ by $1$ .

$\sin (\frac{π}{4} - x) = \frac{- \sqrt{3}}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$\sin (\frac{π}{4} - x) = - \frac{\sqrt{3}}{2}$

Step 3

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$\frac{π}{4} - x = \arcsin (- \frac{\sqrt{3}}{2})$

Step 4

Simplify the right side.

The exact value of $\arcsin (- \frac{\sqrt{3}}{2})$ is $- \frac{π}{3}$ .

$\frac{π}{4} - x = - \frac{π}{3}$

Step 5

Move all terms not containing $x$ to the right side of the equation.

Subtract $\frac{π}{4}$ from both sides of the equation.

$- x = - \frac{π}{3} - \frac{π}{4}$

To write $- \frac{π}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- x = - \frac{π}{3} \cdot \frac{4}{4} - \frac{π}{4}$

To write $- \frac{π}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- x = - \frac{π}{3} \cdot \frac{4}{4} - \frac{π}{4} \cdot \frac{3}{3}$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{π}{3}$ by $\frac{4}{4}$ .

$- x = - \frac{π \cdot 4}{3 \cdot 4} - \frac{π}{4} \cdot \frac{3}{3}$

Multiply $3$ by $4$ .

$- x = - \frac{π \cdot 4}{12} - \frac{π}{4} \cdot \frac{3}{3}$

Multiply $\frac{π}{4}$ by $\frac{3}{3}$ .

$- x = - \frac{π \cdot 4}{12} - \frac{π \cdot 3}{4 \cdot 3}$

Multiply $4$ by $3$ .

$- x = - \frac{π \cdot 4}{12} - \frac{π \cdot 3}{12}$

Combine the numerators over the common denominator.

$- x = \frac{- π \cdot 4 - π \cdot 3}{12}$

Simplify the numerator.

Multiply $4$ by $- 1$ .

$- x = \frac{- 4 π - π \cdot 3}{12}$

Multiply $3$ by $- 1$ .

$- x = \frac{- 4 π - 3 π}{12}$

Subtract $3 π$ from $- 4 π$ .

$- x = \frac{- 7 π}{12}$

Move the negative in front of the fraction.

$- x = - \frac{7 π}{12}$

Step 6

Divide each term in $- x = - \frac{7 π}{12}$ by $- 1$ and simplify.

Divide each term in $- x = - \frac{7 π}{12}$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- \frac{7 π}{12}}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- \frac{7 π}{12}}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- \frac{7 π}{12}}{- 1}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{\frac{7 π}{12}}{1}$

Divide $\frac{7 π}{12}$ by $1$ .

$x = \frac{7 π}{12}$

Step 7

The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from $2 π$ , to find a reference angle. Next, add this reference angle to $π$ to find the solution in the third quadrant.

$\frac{π}{4} - x = 2 π + \frac{π}{3} + π$

Step 8

Simplify the expression to find the second solution.

Subtract $2 π$ from $2 π + \frac{π}{3} + π$ .

$\frac{π}{4} - x = 2 π + \frac{π}{3} + π - 2 π$

The resulting angle of $\frac{4 π}{3}$ is positive, less than $2 π$ , and coterminal with $2 π + \frac{π}{3} + π$ .

$\frac{π}{4} - x = \frac{4 π}{3}$

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $\frac{π}{4}$ from both sides of the equation.

$- x = \frac{4 π}{3} - \frac{π}{4}$

To write $\frac{4 π}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- x = \frac{4 π}{3} \cdot \frac{4}{4} - \frac{π}{4}$

To write $- \frac{π}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- x = \frac{4 π}{3} \cdot \frac{4}{4} - \frac{π}{4} \cdot \frac{3}{3}$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{4 π}{3}$ by $\frac{4}{4}$ .

$- x = \frac{4 π \cdot 4}{3 \cdot 4} - \frac{π}{4} \cdot \frac{3}{3}$

Multiply $3$ by $4$ .

$- x = \frac{4 π \cdot 4}{12} - \frac{π}{4} \cdot \frac{3}{3}$

Multiply $\frac{π}{4}$ by $\frac{3}{3}$ .

$- x = \frac{4 π \cdot 4}{12} - \frac{π \cdot 3}{4 \cdot 3}$

Multiply $4$ by $3$ .

$- x = \frac{4 π \cdot 4}{12} - \frac{π \cdot 3}{12}$

Combine the numerators over the common denominator.

$- x = \frac{4 π \cdot 4 - π \cdot 3}{12}$

Simplify the numerator.

Multiply $4$ by $4$ .

$- x = \frac{16 π - π \cdot 3}{12}$

Multiply $3$ by $- 1$ .

$- x = \frac{16 π - 3 π}{12}$

Subtract $3 π$ from $16 π$ .

$- x = \frac{13 π}{12}$

Divide each term in $- x = \frac{13 π}{12}$ by $- 1$ and simplify.

Divide each term in $- x = \frac{13 π}{12}$ by $- 1$ .

$\frac{- x}{- 1} = \frac{\frac{13 π}{12}}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{\frac{13 π}{12}}{- 1}$

Divide $x$ by $1$ .

$x = \frac{\frac{13 π}{12}}{- 1}$

Simplify the right side.

Move the negative one from the denominator of $\frac{\frac{13 π}{12}}{- 1}$ .

$x = - 1 \cdot \frac{13 π}{12}$

Rewrite $- 1 \cdot \frac{13 π}{12}$ as $- \frac{13 π}{12}$ .

$x = - \frac{13 π}{12}$

Step 9

Find the period of $\sin (\frac{π}{4} - x)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $- 1$ in the formula for period.

$\frac{2 π}{| - 1 |}$

The absolute value is the distance between a number and zero. The distance between $- 1$ and $0$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

Step 10

Add $2 π$ to every negative angle to get positive angles.

Add $2 π$ to $- \frac{13 π}{12}$ to find the positive angle.

$- \frac{13 π}{12} + 2 π$

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{12}{12}$ .

$2 π \cdot \frac{12}{12} - \frac{13 π}{12}$

Combine fractions.

Combine $2 π$ and $\frac{12}{12}$ .

$\frac{2 π \cdot 12}{12} - \frac{13 π}{12}$

Combine the numerators over the common denominator.

$\frac{2 π \cdot 12 - 13 π}{12}$

Simplify the numerator.

Multiply $12$ by $2$ .

$\frac{24 π - 13 π}{12}$

Subtract $13 π$ from $24 π$ .

$\frac{11 π}{12}$

List the new angles.

$x = \frac{11 π}{12}$

Step 11

The period of the $\sin (\frac{π}{4} - x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{7 π}{12} + 2 π n, \frac{11 π}{12} + 2 π n$ , for any integer $n$

Solve for x 2sin(pi/4-x)+ square root of 3=0

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