Solve for x 2sin(x)^2- square root of 3=0

$2 \sin^{2} (x) - \sqrt{3} = 0$

Step 1

Add $\sqrt{3}$ to both sides of the equation.

$2 \sin^{2} (x) = \sqrt{3}$

Step 2

Divide each term in $2 \sin^{2} (x) = \sqrt{3}$ by $2$ and simplify.

Divide each term in $2 \sin^{2} (x) = \sqrt{3}$ by $2$ .

$\frac{2 \sin^{2} (x)}{2} = \frac{\sqrt{3}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sin^{2} (x)}{2} = \frac{\sqrt{3}}{2}$

Divide $\sin^{2} (x)$ by $1$ .

$\sin^{2} (x) = \frac{\sqrt{3}}{2}$

Step 3

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$\sin (x) = \pm \sqrt{\frac{\sqrt{3}}{2}}$

Step 4

Simplify $\pm \sqrt{\frac{\sqrt{3}}{2}}$ .

Rewrite $\sqrt{\frac{\sqrt{3}}{2}}$ as $\frac{\sqrt{\sqrt{3}}}{\sqrt{2}}$ .

$\sin (x) = \pm \frac{\sqrt{\sqrt{3}}}{\sqrt{2}}$

Rewrite $\sqrt{\sqrt{3}}$ as $\sqrt[4]{3}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3}}{\sqrt{2}}$

Multiply $\frac{\sqrt[4]{3}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Combine and simplify the denominator.

Multiply $\frac{\sqrt[4]{3}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{\sqrt{2} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{{\sqrt{2}}^{1 + 1}}$

Add $1$ and $1$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{{\sqrt{2}}^{2}}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{{(2^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{2^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{2^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{2^{\frac{2}{2}}}$

Rewrite the expression.

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{2^{1}}$

Evaluate the exponent.

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt{2}}{2}$

Simplify the numerator.

Rewrite the expression using the least common index of $4$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \cdot 2^{\frac{1}{2}}}{2}$

Rewrite $2^{\frac{1}{2}}$ as $2^{\frac{2}{4}}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \cdot 2^{\frac{2}{4}}}{2}$

Rewrite $2^{\frac{2}{4}}$ as $\sqrt[4]{2^{2}}$ .

$\sin (x) = \pm \frac{\sqrt[4]{3} \sqrt[4]{2^{2}}}{2}$

Combine using the product rule for radicals.

$\sin (x) = \pm \frac{\sqrt[4]{3 \cdot 2^{2}}}{2}$

Raise $2$ to the power of $2$ .

$\sin (x) = \pm \frac{\sqrt[4]{3 \cdot 4}}{2}$

Multiply $3$ by $4$ .

$\sin (x) = \pm \frac{\sqrt[4]{12}}{2}$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$\sin (x) = \frac{\sqrt[4]{12}}{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$\sin (x) = - \frac{\sqrt[4]{12}}{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$\sin (x) = \frac{\sqrt[4]{12}}{2}, - \frac{\sqrt[4]{12}}{2}$

Step 6

Set up each of the solutions to solve for $x$ .

$\sin (x) = \frac{\sqrt[4]{12}}{2}$

$\sin (x) = - \frac{\sqrt[4]{12}}{2}$

Step 7

Solve for $x$ in $\sin (x) = \frac{\sqrt[4]{12}}{2}$ .

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$x = \arcsin (\frac{\sqrt[4]{12}}{2})$

Simplify the right side.

Evaluate $\arcsin (\frac{\sqrt[4]{12}}{2})$ .

$x = 1.19606189$

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $π$ to find the solution in the second quadrant.

$x = (3.14159265) - 1.19606189$

Solve for $x$ .

Remove parentheses.

$x = 3.14159265 - 1.19606189$

Remove parentheses.

$x = (3.14159265) - 1.19606189$

Subtract $1.19606189$ from $3.14159265$ .

$x = 1.94553075$

Find the period of $\sin (x)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

The period of the $\sin (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = 1.19606189 + 2 π n, 1.94553075 + 2 π n$ , for any integer $n$

Step 8

Solve for $x$ in $\sin (x) = - \frac{\sqrt[4]{12}}{2}$ .

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$x = \arcsin (- \frac{\sqrt[4]{12}}{2})$

Simplify the right side.

Evaluate $\arcsin (- \frac{\sqrt[4]{12}}{2})$ .

$x = - 1.19606189$

The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from $2 π$ , to find a reference angle. Next, add this reference angle to $π$ to find the solution in the third quadrant.

$x = 2 (3.14159265) + 1.19606189 + 3.14159265$

Simplify the expression to find the second solution.

Subtract $2 π$ from $2 (3.14159265) + 1.19606189 + 3.14159265$ .

$x = 2 (3.14159265) + 1.19606189 + 3.14159265 - 2 π$

The resulting angle of $4.33765454$ is positive, less than $2 π$ , and coterminal with $2 (3.14159265) + 1.19606189 + 3.14159265$ .

$x = 4.33765454$

Find the period of $\sin (x)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

Add $2 π$ to every negative angle to get positive angles.

Add $2 π$ to $- 1.19606189$ to find the positive angle.

$- 1.19606189 + 2 π$

Subtract $1.19606189$ from $2 π$ .

$5.08712341$

List the new angles.

$x = 5.08712341$

The period of the $\sin (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = 4.33765454 + 2 π n, 5.08712341 + 2 π n$ , for any integer $n$

Step 9

List all of the solutions.

$x = 1.19606189 + 2 π n, 1.94553075 + 2 π n, 4.33765454 + 2 π n, 5.08712341 + 2 π n$ , for any integer $n$

Step 10

Consolidate the solutions.

Consolidate $1.19606189 + 2 π n$ and $4.33765454 + 2 π n$ to $1.19606189 + π n$ .

$x = 1.19606189 + π n, 1.94553075 + 2 π n, 5.08712341 + 2 π n$ , for any integer $n$

Consolidate $1.94553075 + 2 π n$ and $5.08712341 + 2 π n$ to $1.94553075 + π n$ .

$x = 1.19606189 + π n, 1.94553075 + π n$ , for any integer $n$

Solve for x 2sin(x)^2- square root of 3=0

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