Solve for x 2tx+n^3=4f

$2 t x + n^{3} = 4 f$

Subtract $n^{3}$ from both sides of the equation.

$2 t x = 4 f - n^{3}$

Divide each term in $2 t x = 4 f - n^{3}$ by $2 t$ and simplify.

Divide each term in $2 t x = 4 f - n^{3}$ by $2 t$ .

$\frac{2 t x}{2 t} = \frac{4 f}{2 t} + \frac{- n^{3}}{2 t}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 t x}{2 t} = \frac{4 f}{2 t} + \frac{- n^{3}}{2 t}$

Rewrite the expression.

$\frac{t x}{t} = \frac{4 f}{2 t} + \frac{- n^{3}}{2 t}$

Cancel the common factor of $t$ .

Cancel the common factor.

$\frac{t x}{t} = \frac{4 f}{2 t} + \frac{- n^{3}}{2 t}$

Divide $x$ by $1$ .

$x = \frac{4 f}{2 t} + \frac{- n^{3}}{2 t}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4 f$ .

$x = \frac{2 (2 f)}{2 t} + \frac{- n^{3}}{2 t}$

Cancel the common factors.

Factor $2$ out of $2 t$ .

$x = \frac{2 (2 f)}{2 (t)} + \frac{- n^{3}}{2 t}$

Cancel the common factor.

$x = \frac{2 (2 f)}{2 t} + \frac{- n^{3}}{2 t}$

Rewrite the expression.

$x = \frac{2 f}{t} + \frac{- n^{3}}{2 t}$

Move the negative in front of the fraction.

$x = \frac{2 f}{t} - \frac{n^{3}}{2 t}$