Solve for x (2x+1)+(x-10)=90

$(2 x + 1) + (x - 10) = 90$

Simplify $2 x + 1 + x - 10$ .

Add $2 x$ and $x$ .

$3 x + 1 - 10 = 90$

Subtract $10$ from $1$ .

$3 x - 9 = 90$

Move all terms not containing $x$ to the right side of the equation.

Add $9$ to both sides of the equation.

$3 x = 90 + 9$

Add $90$ and $9$ .

$3 x = 99$

Divide each term in $3 x = 99$ by $3$ and simplify.

Divide each term in $3 x = 99$ by $3$ .

$\frac{3 x}{3} = \frac{99}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{99}{3}$

Divide $x$ by $1$ .

$x = \frac{99}{3}$

Simplify the right side.

Divide $99$ by $3$ .

$x = 33$