Solve for x -2x+2=(1/3)^x+1

$- 2 x + 2 = {(\frac{1}{3})}^{x} + 1$

Step 1

Simplify each term.

Apply the product rule to $\frac{1}{3}$ .

$- 2 x + 2 = \frac{1^{x}}{3^{x}} + 1$

One to any power is one.

$- 2 x + 2 = \frac{1}{3^{x}} + 1$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x = - 1, 0$

Step 3