Solve for x 2x+2-3x+5=3+2

$2 x + 2 - 3 x + 5 = 3 + 2$

Simplify $2 x + 2 - 3 x + 5$ .

Subtract $3 x$ from $2 x$ .

$- x + 2 + 5 = 3 + 2$

Add $2$ and $5$ .

$- x + 7 = 3 + 2$

Add $3$ and $2$ .

$- x + 7 = 5$

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- x = 5 - 7$

Subtract $7$ from $5$ .

$- x = - 2$

Divide each term in $- x = - 2$ by $- 1$ and simplify.

Divide each term in $- x = - 2$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 2}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 2}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 2}{- 1}$

Simplify the right side.

Divide $- 2$ by $- 1$ .

$x = 2$