Solve for x 2x^2-4x=0

$2 x^{2} - 4 x = 0$

Step 1

Factor $2 x$ out of $2 x^{2} - 4 x$ .

Factor $2 x$ out of $2 x^{2}$ .

$2 x (x) - 4 x = 0$

Factor $2 x$ out of $- 4 x$ .

$2 x (x) + 2 x (- 2) = 0$

Factor $2 x$ out of $2 x (x) + 2 x (- 2)$ .

$2 x (x - 2) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x - 2 = 0$

Step 3

Set $x$ equal to $0$ .

$x = 0$

Step 4

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Step 5

The final solution is all the values that make $2 x (x - 2) = 0$ true.

$x = 0, 2$