Solve for x (2x-20)/3=2x

$\frac{2 x - 20}{3} = 2 x$

Multiply both sides by $3$ .

$\frac{2 x - 20}{3} \cdot 3 = 2 x \cdot 3$

Simplify.

Simplify the left side.

Simplify $\frac{2 x - 20}{3} \cdot 3$ .

Factor $2$ out of $2 x - 20$ .

Factor $2$ out of $2 x$ .

$\frac{2 (x) - 20}{3} \cdot 3 = 2 x \cdot 3$

Factor $2$ out of $- 20$ .

$\frac{2 x + 2 \cdot - 10}{3} \cdot 3 = 2 x \cdot 3$

Factor $2$ out of $2 x + 2 \cdot - 10$ .

$\frac{2 (x - 10)}{3} \cdot 3 = 2 x \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{2 (x - 10)}{3} \cdot 3 = 2 x \cdot 3$

Rewrite the expression.

$2 (x - 10) = 2 x \cdot 3$

Apply the distributive property.

$2 x + 2 \cdot - 10 = 2 x \cdot 3$

Multiply $2$ by $- 10$ .

$2 x - 20 = 2 x \cdot 3$

Simplify the right side.

Multiply $3$ by $2$ .

$2 x - 20 = 6 x$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$2 x - 20 - 6 x = 0$

Subtract $6 x$ from $2 x$ .

$- 4 x - 20 = 0$

Add $20$ to both sides of the equation.

$- 4 x = 20$

Divide each term in $- 4 x = 20$ by $- 4$ and simplify.

Divide each term in $- 4 x = 20$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{20}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{20}{- 4}$

Divide $x$ by $1$ .

$x = \frac{20}{- 4}$

Simplify the right side.

Divide $20$ by $- 4$ .

$x = - 5$