Solve for x (2x)/3+1=3

$\frac{2 x}{3} + 1 = 3$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$\frac{2 x}{3} = 3 - 1$

Subtract $1$ from $3$ .

$\frac{2 x}{3} = 2$

Step 2

Multiply both sides of the equation by $\frac{3}{2}$ .

$\frac{3}{2} \cdot \frac{2 x}{3} = \frac{3}{2} \cdot 2$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{2} \cdot \frac{2 x}{3}$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{2} \cdot \frac{2 x}{3} = \frac{3}{2} \cdot 2$

Rewrite the expression.

$\frac{1}{2} (2 x) = \frac{3}{2} \cdot 2$

Cancel the common factor of $2$ .

Factor $2$ out of $2 x$ .

$\frac{1}{2} (2 (x)) = \frac{3}{2} \cdot 2$

Cancel the common factor.

$\frac{1}{2} (2 x) = \frac{3}{2} \cdot 2$

Rewrite the expression.

$x = \frac{3}{2} \cdot 2$

Simplify the right side.

Cancel the common factor of $2$ .

Cancel the common factor.

$x = \frac{3}{2} \cdot 2$

Rewrite the expression.

$x = 3$