Solve for x -2x+3y>=3

$- 2 x + 3 y \geq 3$

Step 1

Subtract $3 y$ from both sides of the inequality.

$- 2 x \geq 3 - 3 y$

Step 2

Divide each term in $- 2 x \geq 3 - 3 y$ by $- 2$ and simplify.

Divide each term in $- 2 x \geq 3 - 3 y$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} \leq \frac{3}{- 2} + \frac{- 3 y}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} \leq \frac{3}{- 2} + \frac{- 3 y}{- 2}$

Divide $x$ by $1$ .

$x \leq \frac{3}{- 2} + \frac{- 3 y}{- 2}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$x \leq - \frac{3}{2} + \frac{- 3 y}{- 2}$

Dividing two negative values results in a positive value.

$x \leq - \frac{3}{2} + \frac{3 y}{2}$

Solve for x -2x+3y>=3

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