Solve for x 2x+4+3x-1=7x-2-x

$2 x + 4 + 3 x - 1 = 7 x - 2 - x$

Step 1

Simplify $2 x + 4 + 3 x - 1$ .

Add $2 x$ and $3 x$ .

$5 x + 4 - 1 = 7 x - 2 - x$

Subtract $1$ from $4$ .

$5 x + 3 = 7 x - 2 - x$

Step 2

Subtract $x$ from $7 x$ .

$5 x + 3 = 6 x - 2$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$5 x + 3 - 6 x = - 2$

Subtract $6 x$ from $5 x$ .

$- x + 3 = - 2$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- x = - 2 - 3$

Subtract $3$ from $- 2$ .

$- x = - 5$

Step 5

Divide each term in $- x = - 5$ by $- 1$ and simplify.

Divide each term in $- x = - 5$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 5}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 5}{- 1}$

Simplify the right side.

Divide $- 5$ by $- 1$ .

$x = 5$