Solve for x (2x+5)/10=42/20

$\frac{2 x + 5}{10} = \frac{42}{20}$

Multiply both sides by $10$ .

$\frac{2 x + 5}{10} \cdot 10 = \frac{42}{20} \cdot 10$

Simplify.

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{2 x + 5}{10} \cdot 10 = \frac{42}{20} \cdot 10$

Rewrite the expression.

$2 x + 5 = \frac{42}{20} \cdot 10$

Simplify the right side.

Simplify $\frac{42}{20} \cdot 10$ .

Cancel the common factor of $10$ .

Factor $10$ out of $20$ .

$2 x + 5 = \frac{42}{10 (2)} \cdot 10$

Cancel the common factor.

$2 x + 5 = \frac{42}{10 \cdot 2} \cdot 10$

Rewrite the expression.

$2 x + 5 = \frac{42}{2}$

Divide $42$ by $2$ .

$2 x + 5 = 21$

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$2 x = 21 - 5$

Subtract $5$ from $21$ .

$2 x = 16$

Divide each term in $2 x = 16$ by $2$ and simplify.

Divide each term in $2 x = 16$ by $2$ .

$\frac{2 x}{2} = \frac{16}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{16}{2}$

Divide $x$ by $1$ .

$x = \frac{16}{2}$

Simplify the right side.

Divide $16$ by $2$ .

$x = 8$