Solve for x (2x-6)/2+3=10

$\frac{2 x - 6}{2} + 3 = 10$

Step 1

Cancel the common factor of $2 x - 6$ and $2$ .

Factor $2$ out of $2 x$ .

$\frac{2 (x) - 6}{2} + 3 = 10$

Factor $2$ out of $- 6$ .

$\frac{2 (x) + 2 \cdot - 3}{2} + 3 = 10$

Factor $2$ out of $2 (x) + 2 (- 3)$ .

$\frac{2 (x - 3)}{2} + 3 = 10$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 (x - 3)}{2 (1)} + 3 = 10$

Cancel the common factor.

$\frac{2 (x - 3)}{2 \cdot 1} + 3 = 10$

Rewrite the expression.

$\frac{x - 3}{1} + 3 = 10$

Divide $x - 3$ by $1$ .

$x - 3 + 3 = 10$

$x - 3 + 3 = 10$

$x - 3 + 3 = 10$

Step 2

Combine the opposite terms in $x - 3 + 3$ .

Add $- 3$ and $3$ .

$x + 0 = 10$

Add $x$ and $0$ .

$x = 10$

$x = 10$

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