Solve for x 2x-7+19=6x-4x+12

$2 x - 7 + 19 = 6 x - 4 x + 12$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$6 x - 4 x + 12 = 2 x - 7 + 19$

Step 2

Subtract $4 x$ from $6 x$ .

$2 x + 12 = 2 x - 7 + 19$

Step 3

Add $- 7$ and $19$ .

$2 x + 12 = 2 x + 12$

Step 4

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$2 x + 12 - 2 x = 12$

Combine the opposite terms in $2 x + 12 - 2 x$ .

Subtract $2 x$ from $2 x$ .

$0 + 12 = 12$

Add $0$ and $12$ .

$12 = 12$

Step 5

Since $12 = 12$ , the equation will always be true for any value of $x$ .

All real numbers

Step 6

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$