Solve for x 2x+7+x=5+4x-3

$2 x + 7 + x = 5 + 4 x - 3$

Add $2 x$ and $x$ .

$3 x + 7 = 5 + 4 x - 3$

Subtract $3$ from $5$ .

$3 x + 7 = 4 x + 2$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$3 x + 7 - 4 x = 2$

Subtract $4 x$ from $3 x$ .

$- x + 7 = 2$

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- x = 2 - 7$

Subtract $7$ from $2$ .

$- x = - 5$

Divide each term in $- x = - 5$ by $- 1$ and simplify.

Divide each term in $- x = - 5$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 5}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 5}{- 1}$

Simplify the right side.

Divide $- 5$ by $- 1$ .

$x = 5$