Solve for x 2x- square root of 3=6

$2 x - \sqrt{3} = 6$

Step 1

Add $\sqrt{3}$ to both sides of the equation.

$2 x = 6 + \sqrt{3}$

Step 2

Divide each term in $2 x = 6 + \sqrt{3}$ by $2$ and simplify.

Divide each term in $2 x = 6 + \sqrt{3}$ by $2$ .

$\frac{2 x}{2} = \frac{6}{2} + \frac{\sqrt{3}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{6}{2} + \frac{\sqrt{3}}{2}$

Divide $x$ by $1$ .

$x = \frac{6}{2} + \frac{\sqrt{3}}{2}$

Simplify the right side.

Divide $6$ by $2$ .

$x = 3 + \frac{\sqrt{3}}{2}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = 3 + \frac{\sqrt{3}}{2}$

Decimal Form:

$x = 3.86602540 \dots$