Solve for x 2x+x+(2x-3)+2x+(x-1)=76

$2 x + x + (2 x - 3) + 2 x + (x - 1) = 76$

Step 1

Simplify $2 x + x + 2 x - 3 + 2 x + x - 1$ .

Add $2 x$ and $x$ .

$3 x + 2 x - 3 + 2 x + x - 1 = 76$

Add $3 x$ and $2 x$ .

$5 x - 3 + 2 x + x - 1 = 76$

Add $5 x$ and $2 x$ .

$7 x - 3 + x - 1 = 76$

Add $7 x$ and $x$ .

$8 x - 3 - 1 = 76$

Subtract $1$ from $- 3$ .

$8 x - 4 = 76$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$8 x = 76 + 4$

Add $76$ and $4$ .

$8 x = 80$

Step 3

Divide each term in $8 x = 80$ by $8$ and simplify.

Divide each term in $8 x = 80$ by $8$ .

$\frac{8 x}{8} = \frac{80}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{80}{8}$

Divide $x$ by $1$ .

$x = \frac{80}{8}$

Simplify the right side.

Divide $80$ by $8$ .

$x = 10$