Solve for x (2x)/(x+8)=(2x-8)/x

$\frac{2 x}{x + 8} = \frac{2 x - 8}{x}$

Factor $2$ out of $2 x - 8$ .

Factor $2$ out of $2 x$ .

$\frac{2 x}{x + 8} = \frac{2 (x) - 8}{x}$

Factor $2$ out of $- 8$ .

$\frac{2 x}{x + 8} = \frac{2 x + 2 \cdot - 4}{x}$

Factor $2$ out of $2 x + 2 \cdot - 4$ .

$\frac{2 x}{x + 8} = \frac{2 (x - 4)}{x}$

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$2 x \cdot x = (x + 8) (2 (x - 4))$

Solve the equation for $x$ .

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$2 (x \cdot x) = (x + 8) \cdot (2 (x - 4))$

Multiply $x$ by $x$ .

$2 x^{2} = (x + 8) \cdot (2 (x - 4))$

Simplify $(x + 8) \cdot (2 (x - 4))$ .

Simplify by multiplying through.

Apply the distributive property.

$2 x^{2} = (x + 8) \cdot (2 x + 2 \cdot - 4)$

Multiply $2$ by $- 4$ .

$2 x^{2} = (x + 8) \cdot (2 x - 8)$

Expand $(x + 8) (2 x - 8)$ using the FOIL Method.

Apply the distributive property.

$2 x^{2} = x (2 x - 8) + 8 (2 x - 8)$

Apply the distributive property.

$2 x^{2} = x (2 x) + x \cdot - 8 + 8 (2 x - 8)$

Apply the distributive property.

$2 x^{2} = x (2 x) + x \cdot - 8 + 8 (2 x) + 8 \cdot - 8$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$2 x^{2} = 2 x \cdot x + x \cdot - 8 + 8 (2 x) + 8 \cdot - 8$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$2 x^{2} = 2 (x \cdot x) + x \cdot - 8 + 8 (2 x) + 8 \cdot - 8$

Multiply $x$ by $x$ .

$2 x^{2} = 2 x^{2} + x \cdot - 8 + 8 (2 x) + 8 \cdot - 8$

Move $- 8$ to the left of $x$ .

$2 x^{2} = 2 x^{2} - 8 \cdot x + 8 (2 x) + 8 \cdot - 8$

Multiply $2$ by $8$ .

$2 x^{2} = 2 x^{2} - 8 x + 16 x + 8 \cdot - 8$

Multiply $8$ by $- 8$ .

$2 x^{2} = 2 x^{2} - 8 x + 16 x - 64$

Add $- 8 x$ and $16 x$ .

$2 x^{2} = 2 x^{2} + 8 x - 64$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 x^{2} + 8 x - 64 = 2 x^{2}$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x^{2}$ from both sides of the equation.

$2 x^{2} + 8 x - 64 - 2 x^{2} = 0$

Combine the opposite terms in $2 x^{2} + 8 x - 64 - 2 x^{2}$ .

Subtract $2 x^{2}$ from $2 x^{2}$ .

$8 x - 64 + 0 = 0$

Add $8 x - 64$ and $0$ .

$8 x - 64 = 0$

Add $64$ to both sides of the equation.

$8 x = 64$

Divide each term in $8 x = 64$ by $8$ and simplify.

Divide each term in $8 x = 64$ by $8$ .

$\frac{8 x}{8} = \frac{64}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{64}{8}$

Divide $x$ by $1$ .

$x = \frac{64}{8}$

Simplify the right side.

Divide $64$ by $8$ .

$x = 8$

Solve for x (2x)/(x+8)=(2x-8)/x

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