Solve for x 2x+y=8

$2 x + y = 8$

Step 1

Subtract $y$ from both sides of the equation.

$2 x = 8 - y$

Step 2

Divide each term in $2 x = 8 - y$ by $2$ and simplify.

Divide each term in $2 x = 8 - y$ by $2$ .

$\frac{2 x}{2} = \frac{8}{2} + \frac{- y}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{8}{2} + \frac{- y}{2}$

Divide $x$ by $1$ .

$x = \frac{8}{2} + \frac{- y}{2}$

Simplify the right side.

Simplify each term.

Divide $8$ by $2$ .

$x = 4 + \frac{- y}{2}$

Move the negative in front of the fraction.

$x = 4 - \frac{y}{2}$