Solve for x 3(2x-1)+x=5x+3

$3 (2 x - 1) + x = 5 x + 3$

Step 1

Simplify $3 (2 x - 1) + x$ .

Simplify each term.

Apply the distributive property.

$3 (2 x) + 3 \cdot - 1 + x = 5 x + 3$

Multiply $2$ by $3$ .

$6 x + 3 \cdot - 1 + x = 5 x + 3$

Multiply $3$ by $- 1$ .

$6 x - 3 + x = 5 x + 3$

Add $6 x$ and $x$ .

$7 x - 3 = 5 x + 3$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $5 x$ from both sides of the equation.

$7 x - 3 - 5 x = 3$

Subtract $5 x$ from $7 x$ .

$2 x - 3 = 3$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$2 x = 3 + 3$

Add $3$ and $3$ .

$2 x = 6$

Step 4

Divide each term in $2 x = 6$ by $2$ and simplify.

Divide each term in $2 x = 6$ by $2$ .

$\frac{2 x}{2} = \frac{6}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{6}{2}$

Divide $x$ by $1$ .

$x = \frac{6}{2}$

Simplify the right side.

Divide $6$ by $2$ .

$x = 3$