Solve for x 3(2x-14)+x=15-(-9x-5)

$3 (2 x - 14) + x = 15 - (- 9 x - 5)$

Simplify $3 (2 x - 14) + x$ .

Simplify each term.

Apply the distributive property.

$3 (2 x) + 3 \cdot - 14 + x = 15 - (- 9 x - 5)$

Multiply $2$ by $3$ .

$6 x + 3 \cdot - 14 + x = 15 - (- 9 x - 5)$

Multiply $3$ by $- 14$ .

$6 x - 42 + x = 15 - (- 9 x - 5)$

Add $6 x$ and $x$ .

$7 x - 42 = 15 - (- 9 x - 5)$

Simplify $15 - (- 9 x - 5)$ .

Simplify each term.

Apply the distributive property.

$7 x - 42 = 15 - (- 9 x) - - 5$

Multiply $- 9$ by $- 1$ .

$7 x - 42 = 15 + 9 x - - 5$

Multiply $- 1$ by $- 5$ .

$7 x - 42 = 15 + 9 x + 5$

Add $15$ and $5$ .

$7 x - 42 = 9 x + 20$

Move all terms containing $x$ to the left side of the equation.

Subtract $9 x$ from both sides of the equation.

$7 x - 42 - 9 x = 20$

Subtract $9 x$ from $7 x$ .

$- 2 x - 42 = 20$

Move all terms not containing $x$ to the right side of the equation.

Add $42$ to both sides of the equation.

$- 2 x = 20 + 42$

Add $20$ and $42$ .

$- 2 x = 62$

Divide each term in $- 2 x = 62$ by $- 2$ and simplify.

Divide each term in $- 2 x = 62$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{62}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{62}{- 2}$

Divide $x$ by $1$ .

$x = \frac{62}{- 2}$

Simplify the right side.

Divide $62$ by $- 2$ .

$x = - 31$