Solve for x 3(2x+4)=2+6x+10

$3 (2 x + 4) = 2 + 6 x + 10$

Step 1

Simplify $3 (2 x + 4)$ .

Rewrite.

$0 + 0 + 3 (2 x + 4) = 2 + 6 x + 10$

Simplify by adding zeros.

$3 (2 x + 4) = 2 + 6 x + 10$

Apply the distributive property.

$3 (2 x) + 3 \cdot 4 = 2 + 6 x + 10$

Multiply.

Multiply $2$ by $3$ .

$6 x + 3 \cdot 4 = 2 + 6 x + 10$

Multiply $3$ by $4$ .

$6 x + 12 = 2 + 6 x + 10$

Step 2

Add $2$ and $10$ .

$6 x + 12 = 6 x + 12$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$6 x + 12 - 6 x = 12$

Combine the opposite terms in $6 x + 12 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 + 12 = 12$

Add $0$ and $12$ .

$12 = 12$

Step 4

Since $12 = 12$ , the equation will always be true for any value of $x$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$