Solve for x 3|2x-5|=21

$3 | 2 x - 5 | = 21$

Step 1

Divide each term in $3 | 2 x - 5 | = 21$ by $3$ and simplify.

Divide each term in $3 | 2 x - 5 | = 21$ by $3$ .

$\frac{3 | 2 x - 5 |}{3} = \frac{21}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 | 2 x - 5 |}{3} = \frac{21}{3}$

Divide $| 2 x - 5 |$ by $1$ .

$| 2 x - 5 | = \frac{21}{3}$

Simplify the right side.

Divide $21$ by $3$ .

$| 2 x - 5 | = 7$

Step 2

Remove the absolute value term. This creates a $\pm$ on the right side of the equation because $| x | = \pm x$ .

$2 x - 5 = \pm 7$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$2 x - 5 = 7$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$2 x = 7 + 5$

Add $7$ and $5$ .

$2 x = 12$

Divide each term in $2 x = 12$ by $2$ and simplify.

Divide each term in $2 x = 12$ by $2$ .

$\frac{2 x}{2} = \frac{12}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{12}{2}$

Divide $x$ by $1$ .

$x = \frac{12}{2}$

Simplify the right side.

Divide $12$ by $2$ .

$x = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$2 x - 5 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$2 x = - 7 + 5$

Add $- 7$ and $5$ .

$2 x = - 2$

Divide each term in $2 x = - 2$ by $2$ and simplify.

Divide each term in $2 x = - 2$ by $2$ .

$\frac{2 x}{2} = \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 2}{2}$

Divide $x$ by $1$ .

$x = \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 6, - 1$

Solve for x 3|2x-5|=21

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