Solve for x 3+3x-1=x+2+2x

$3 + 3 x - 1 = x + 2 + 2 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x + 2 + 2 x = 3 + 3 x - 1$

Add $x$ and $2 x$ .

$3 x + 2 = 3 + 3 x - 1$

Subtract $1$ from $3$ .

$3 x + 2 = 3 x + 2$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$3 x + 2 - 3 x = 2$

Combine the opposite terms in $3 x + 2 - 3 x$ .

Subtract $3 x$ from $3 x$ .

$0 + 2 = 2$

Add $0$ and $2$ .

$2 = 2$

Since $2 = 2$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$