Solve for x -3/4(16x+8)=19-(10x-3)

$- \frac{3}{4} (16 x + 8) = 19 - (10 x - 3)$

Simplify $- \frac{3}{4} \cdot (16 x + 8)$ .

Rewrite.

$0 + 0 - \frac{3}{4} \cdot (16 x + 8) = 19 - (10 x - 3)$

Simplify by adding zeros.

$- \frac{3}{4} \cdot (16 x + 8) = 19 - (10 x - 3)$

Apply the distributive property.

$- \frac{3}{4} (16 x) - \frac{3}{4} \cdot 8 = 19 - (10 x - 3)$

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{3}{4}$ into the numerator.

$\frac{- 3}{4} (16 x) - \frac{3}{4} \cdot 8 = 19 - (10 x - 3)$

Factor $4$ out of $16 x$ .

$\frac{- 3}{4} (4 (4 x)) - \frac{3}{4} \cdot 8 = 19 - (10 x - 3)$

Cancel the common factor.

$\frac{- 3}{4} (4 (4 x)) - \frac{3}{4} \cdot 8 = 19 - (10 x - 3)$

Rewrite the expression.

$- 3 (4 x) - \frac{3}{4} \cdot 8 = 19 - (10 x - 3)$

Multiply $4$ by $- 3$ .

$- 12 x - \frac{3}{4} \cdot 8 = 19 - (10 x - 3)$

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{3}{4}$ into the numerator.

$- 12 x + \frac{- 3}{4} \cdot 8 = 19 - (10 x - 3)$

Factor $4$ out of $8$ .

$- 12 x + \frac{- 3}{4} \cdot (4 (2)) = 19 - (10 x - 3)$

Cancel the common factor.

$- 12 x + \frac{- 3}{4} \cdot (4 \cdot 2) = 19 - (10 x - 3)$

Rewrite the expression.

$- 12 x - 3 \cdot 2 = 19 - (10 x - 3)$

Multiply $- 3$ by $2$ .

$- 12 x - 6 = 19 - (10 x - 3)$

Simplify $19 - (10 x - 3)$ .

Simplify each term.

Apply the distributive property.

$- 12 x - 6 = 19 - (10 x) - - 3$

Multiply $10$ by $- 1$ .

$- 12 x - 6 = 19 - 10 x - - 3$

Multiply $- 1$ by $- 3$ .

$- 12 x - 6 = 19 - 10 x + 3$

Add $19$ and $3$ .

$- 12 x - 6 = - 10 x + 22$

Move all terms containing $x$ to the left side of the equation.

Add $10 x$ to both sides of the equation.

$- 12 x - 6 + 10 x = 22$

Add $- 12 x$ and $10 x$ .

$- 2 x - 6 = 22$

Move all terms not containing $x$ to the right side of the equation.

Add $6$ to both sides of the equation.

$- 2 x = 22 + 6$

Add $22$ and $6$ .

$- 2 x = 28$

Divide each term in $- 2 x = 28$ by $- 2$ and simplify.

Divide each term in $- 2 x = 28$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{28}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{28}{- 2}$

Divide $x$ by $1$ .

$x = \frac{28}{- 2}$

Simplify the right side.

Divide $28$ by $- 2$ .

$x = - 14$

Solve for x -3/4(16x+8)=19-(10x-3)

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