Solve for x 3/4(2-mx)=12

$\frac{3}{4} (2 - m x) = 12$

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} (\frac{3}{4} \cdot (2 - m x)) = \frac{4}{3} \cdot 12$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} (\frac{3}{4} \cdot (2 - m x))$ .

Apply the distributive property.

$\frac{4}{3} (\frac{3}{4} \cdot 2 + \frac{3}{4} (- m x)) = \frac{4}{3} \cdot 12$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{4}{3} (\frac{3}{2 (2)} \cdot 2 + \frac{3}{4} (- m x)) = \frac{4}{3} \cdot 12$

Cancel the common factor.

$\frac{4}{3} (\frac{3}{2 \cdot 2} \cdot 2 + \frac{3}{4} (- m x)) = \frac{4}{3} \cdot 12$

Rewrite the expression.

$\frac{4}{3} (\frac{3}{2} + \frac{3}{4} (- m x)) = \frac{4}{3} \cdot 12$

Multiply $\frac{3}{4} (- m x)$ .

Combine $\frac{3}{4}$ and $m$ .

$\frac{4}{3} (\frac{3}{2} - \frac{3 m}{4} x) = \frac{4}{3} \cdot 12$

Combine $x$ and $\frac{3 m}{4}$ .

$\frac{4}{3} (\frac{3}{2} - \frac{x (3 m)}{4}) = \frac{4}{3} \cdot 12$

Move $3$ to the left of $x$ .

$\frac{4}{3} (\frac{3}{2} - \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Simplify terms.

Apply the distributive property.

$\frac{4}{3} \cdot \frac{3}{2} + \frac{4}{3} (- \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{2 (2)}{3} \cdot \frac{3}{2} + \frac{4}{3} (- \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Cancel the common factor.

$\frac{2 \cdot 2}{3} \cdot \frac{3}{2} + \frac{4}{3} (- \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Rewrite the expression.

$\frac{2}{3} \cdot 3 + \frac{4}{3} (- \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{2}{3} \cdot 3 + \frac{4}{3} (- \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Rewrite the expression.

$2 + \frac{4}{3} (- \frac{3 x m}{4}) = \frac{4}{3} \cdot 12$

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{3 x m}{4}$ into the numerator.

$2 + \frac{4}{3} \cdot \frac{- 3 x m}{4} = \frac{4}{3} \cdot 12$

Cancel the common factor.

$2 + \frac{4}{3} \cdot \frac{- 3 x m}{4} = \frac{4}{3} \cdot 12$

Rewrite the expression.

$2 + \frac{1}{3} (- 3 x m) = \frac{4}{3} \cdot 12$

Cancel the common factor of $3$ .

Factor $3$ out of $- 3 x m$ .

$2 + \frac{1}{3} (3 (- x m)) = \frac{4}{3} \cdot 12$

Cancel the common factor.

$2 + \frac{1}{3} (3 (- x m)) = \frac{4}{3} \cdot 12$

Rewrite the expression.

$2 - x m = \frac{4}{3} \cdot 12$

Simplify the right side.

Simplify $\frac{4}{3} \cdot 12$ .

Cancel the common factor of $3$ .

Factor $3$ out of $12$ .

$2 - x m = \frac{4}{3} \cdot (3 (4))$

Cancel the common factor.

$2 - x m = \frac{4}{3} \cdot (3 \cdot 4)$

Rewrite the expression.

$2 - x m = 4 \cdot 4$

Multiply $4$ by $4$ .

$2 - x m = 16$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$- x m = 16 - 2$

Subtract $2$ from $16$ .

$- x m = 14$

Divide each term in $- x m = 14$ by $- 1 m$ and simplify.

Divide each term in $- x m = 14$ by $- 1 m$ .

$\frac{- x m}{- 1 m} = \frac{14}{- 1 m}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x m}{m} = \frac{14}{- 1 m}$

Cancel the common factor of $m$ .

Cancel the common factor.

$\frac{x m}{m} = \frac{14}{- 1 m}$

Divide $x$ by $1$ .

$x = \frac{14}{- 1 m}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{14}{m}$

Solve for x 3/4(2-mx)=12

Related Questions

Support LCMGCF.com by disabling your adblocker.