Solve for x 3/4(2x+1)=2

$\frac{3}{4} (2 x + 1) = 2$

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} (\frac{3}{4} \cdot (2 x + 1)) = \frac{4}{3} \cdot 2$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} (\frac{3}{4} \cdot (2 x + 1))$ .

Apply the distributive property.

$\frac{4}{3} (\frac{3}{4} (2 x) + \frac{3}{4} \cdot 1) = \frac{4}{3} \cdot 2$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{4}{3} (\frac{3}{2 (2)} (2 x) + \frac{3}{4} \cdot 1) = \frac{4}{3} \cdot 2$

Factor $2$ out of $2 x$ .

$\frac{4}{3} (\frac{3}{2 (2)} (2 (x)) + \frac{3}{4} \cdot 1) = \frac{4}{3} \cdot 2$

Cancel the common factor.

$\frac{4}{3} (\frac{3}{2 \cdot 2} (2 x) + \frac{3}{4} \cdot 1) = \frac{4}{3} \cdot 2$

Rewrite the expression.

$\frac{4}{3} (\frac{3}{2} x + \frac{3}{4} \cdot 1) = \frac{4}{3} \cdot 2$

Combine $\frac{3}{2}$ and $x$ .

$\frac{4}{3} (\frac{3 x}{2} + \frac{3}{4} \cdot 1) = \frac{4}{3} \cdot 2$

Multiply $\frac{3}{4}$ by $1$ .

$\frac{4}{3} (\frac{3 x}{2} + \frac{3}{4}) = \frac{4}{3} \cdot 2$

Apply the distributive property.

$\frac{4}{3} \cdot \frac{3 x}{2} + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{2 (2)}{3} \cdot \frac{3 x}{2} + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Cancel the common factor.

$\frac{2 \cdot 2}{3} \cdot \frac{3 x}{2} + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Rewrite the expression.

$\frac{2}{3} (3 x) + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Cancel the common factor of $3$ .

Factor $3$ out of $3 x$ .

$\frac{2}{3} (3 (x)) + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Cancel the common factor.

$\frac{2}{3} (3 x) + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Rewrite the expression.

$2 x + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Cancel the common factor of $4$ .

Cancel the common factor.

$2 x + \frac{4}{3} \cdot \frac{3}{4} = \frac{4}{3} \cdot 2$

Rewrite the expression.

$2 x + \frac{1}{3} \cdot 3 = \frac{4}{3} \cdot 2$

Cancel the common factor of $3$ .

Cancel the common factor.

$2 x + \frac{1}{3} \cdot 3 = \frac{4}{3} \cdot 2$

Rewrite the expression.

$2 x + 1 = \frac{4}{3} \cdot 2$

Simplify the right side.

Multiply $\frac{4}{3} \cdot 2$ .

Combine $\frac{4}{3}$ and $2$ .

$2 x + 1 = \frac{4 \cdot 2}{3}$

Multiply $4$ by $2$ .

$2 x + 1 = \frac{8}{3}$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$2 x = \frac{8}{3} - 1$

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 x = \frac{8}{3} - 1 \cdot \frac{3}{3}$

Combine $- 1$ and $\frac{3}{3}$ .

$2 x = \frac{8}{3} + \frac{- 1 \cdot 3}{3}$

Combine the numerators over the common denominator.

$2 x = \frac{8 - 1 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 1$ by $3$ .

$2 x = \frac{8 - 3}{3}$

Subtract $3$ from $8$ .

$2 x = \frac{5}{3}$

Divide each term in $2 x = \frac{5}{3}$ by $2$ and simplify.

Divide each term in $2 x = \frac{5}{3}$ by $2$ .

$\frac{2 x}{2} = \frac{\frac{5}{3}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{\frac{5}{3}}{2}$

Divide $x$ by $1$ .

$x = \frac{\frac{5}{3}}{2}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{5}{3} \cdot \frac{1}{2}$

Multiply $\frac{5}{3} \cdot \frac{1}{2}$ .

Multiply $\frac{5}{3}$ by $\frac{1}{2}$ .

$x = \frac{5}{3 \cdot 2}$

Multiply $3$ by $2$ .

$x = \frac{5}{6}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{5}{6}$

Decimal Form:

$x = 0.8\overline{3}$

Solve for x 3/4(2x+1)=2

Related Questions

Support LCMGCF.com by disabling your adblocker.