Solve for x 3/4(6x+2)=15

$\frac{3}{4} (6 x + 2) = 15$

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} (\frac{3}{4} \cdot (6 x + 2)) = \frac{4}{3} \cdot 15$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} (\frac{3}{4} \cdot (6 x + 2))$ .

Apply the distributive property.

$\frac{4}{3} (\frac{3}{4} (6 x) + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{4}{3} (\frac{3}{2 (2)} (6 x) + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Factor $2$ out of $6 x$ .

$\frac{4}{3} (\frac{3}{2 (2)} (2 (3 x)) + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Cancel the common factor.

$\frac{4}{3} (\frac{3}{2 \cdot 2} (2 (3 x)) + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Rewrite the expression.

$\frac{4}{3} (\frac{3}{2} (3 x) + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Combine $3$ and $\frac{3}{2}$ .

$\frac{4}{3} (\frac{3 \cdot 3}{2} x + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Multiply $3$ by $3$ .

$\frac{4}{3} (\frac{9}{2} x + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Combine $\frac{9}{2}$ and $x$ .

$\frac{4}{3} (\frac{9 x}{2} + \frac{3}{4} \cdot 2) = \frac{4}{3} \cdot 15$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{4}{3} (\frac{9 x}{2} + \frac{3}{2 (2)} \cdot 2) = \frac{4}{3} \cdot 15$

Cancel the common factor.

$\frac{4}{3} (\frac{9 x}{2} + \frac{3}{2 \cdot 2} \cdot 2) = \frac{4}{3} \cdot 15$

Rewrite the expression.

$\frac{4}{3} (\frac{9 x}{2} + \frac{3}{2}) = \frac{4}{3} \cdot 15$

Apply the distributive property.

$\frac{4}{3} \cdot \frac{9 x}{2} + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{2 (2)}{3} \cdot \frac{9 x}{2} + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Cancel the common factor.

$\frac{2 \cdot 2}{3} \cdot \frac{9 x}{2} + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Rewrite the expression.

$\frac{2}{3} (9 x) + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Cancel the common factor of $3$ .

Factor $3$ out of $9 x$ .

$\frac{2}{3} (3 (3 x)) + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Cancel the common factor.

$\frac{2}{3} (3 (3 x)) + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Rewrite the expression.

$2 (3 x) + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Multiply $3$ by $2$ .

$6 x + \frac{4}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$6 x + \frac{2 (2)}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Cancel the common factor.

$6 x + \frac{2 \cdot 2}{3} \cdot \frac{3}{2} = \frac{4}{3} \cdot 15$

Rewrite the expression.

$6 x + \frac{2}{3} \cdot 3 = \frac{4}{3} \cdot 15$

Cancel the common factor of $3$ .

Cancel the common factor.

$6 x + \frac{2}{3} \cdot 3 = \frac{4}{3} \cdot 15$

Rewrite the expression.

$6 x + 2 = \frac{4}{3} \cdot 15$

Simplify the right side.

Simplify $\frac{4}{3} \cdot 15$ .

Cancel the common factor of $3$ .

Factor $3$ out of $15$ .

$6 x + 2 = \frac{4}{3} \cdot (3 (5))$

Cancel the common factor.

$6 x + 2 = \frac{4}{3} \cdot (3 \cdot 5)$

Rewrite the expression.

$6 x + 2 = 4 \cdot 5$

Multiply $4$ by $5$ .

$6 x + 2 = 20$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$6 x = 20 - 2$

Subtract $2$ from $20$ .

$6 x = 18$

Divide each term in $6 x = 18$ by $6$ and simplify.

Divide each term in $6 x = 18$ by $6$ .

$\frac{6 x}{6} = \frac{18}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{18}{6}$

Divide $x$ by $1$ .

$x = \frac{18}{6}$

Simplify the right side.

Divide $18$ by $6$ .

$x = 3$

Solve for x 3/4(6x+2)=15

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