Solve for x 3(4)(-7)+3(4x)=24

$3 (4) (- 7) + 3 (4 x) = 24$

Simplify each term.

Multiply $3$ by $4$ .

$12 \cdot - 7 + 3 \cdot (4 x) = 24$

Multiply $12$ by $- 7$ .

$- 84 + 3 \cdot (4 x) = 24$

Multiply $4$ by $3$ .

$- 84 + 12 x = 24$

Move all terms not containing $x$ to the right side of the equation.

Add $84$ to both sides of the equation.

$12 x = 24 + 84$

Add $24$ and $84$ .

$12 x = 108$

Divide each term in $12 x = 108$ by $12$ and simplify.

Divide each term in $12 x = 108$ by $12$ .

$\frac{12 x}{12} = \frac{108}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 x}{12} = \frac{108}{12}$

Divide $x$ by $1$ .

$x = \frac{108}{12}$

Simplify the right side.

Divide $108$ by $12$ .

$x = 9$