Solve for x 3/4(x-1)+x=1

$\frac{3}{4} (x - 1) + x = 1$

Simplify $\frac{3}{4} \cdot (x - 1) + x$ .

Simplify each term.

Apply the distributive property.

$\frac{3}{4} x + \frac{3}{4} \cdot - 1 + x = 1$

Combine $\frac{3}{4}$ and $x$ .

$\frac{3 x}{4} + \frac{3}{4} \cdot - 1 + x = 1$

Multiply $\frac{3}{4} \cdot - 1$ .

Combine $\frac{3}{4}$ and $- 1$ .

$\frac{3 x}{4} + \frac{3 \cdot - 1}{4} + x = 1$

Multiply $3$ by $- 1$ .

$\frac{3 x}{4} + \frac{- 3}{4} + x = 1$

Move the negative in front of the fraction.

$\frac{3 x}{4} - \frac{3}{4} + x = 1$

To write $x$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{3 x}{4} + x \cdot \frac{4}{4} - \frac{3}{4} = 1$

Simplify terms.

Combine $x$ and $\frac{4}{4}$ .

$\frac{3 x}{4} + \frac{x \cdot 4}{4} - \frac{3}{4} = 1$

Combine the numerators over the common denominator.

$\frac{3 x + x \cdot 4}{4} - \frac{3}{4} = 1$

Combine the numerators over the common denominator.

$\frac{3 x + x \cdot 4 - 3}{4} = 1$

Move $4$ to the left of $x$ .

$\frac{3 x + 4 x - 3}{4} = 1$

Add $3 x$ and $4 x$ .

$\frac{7 x - 3}{4} = 1$

Multiply both sides by $4$ .

$\frac{7 x - 3}{4} \cdot 4 = 1 \cdot 4$

Simplify.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{7 x - 3}{4} \cdot 4 = 1 \cdot 4$

Rewrite the expression.

$7 x - 3 = 1 \cdot 4$

Simplify the right side.

Multiply $4$ by $1$ .

$7 x - 3 = 4$

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$7 x = 4 + 3$

Add $4$ and $3$ .

$7 x = 7$

Divide each term in $7 x = 7$ by $7$ and simplify.

Divide each term in $7 x = 7$ by $7$ .

$\frac{7 x}{7} = \frac{7}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{7}{7}$

Divide $x$ by $1$ .

$x = \frac{7}{7}$

Simplify the right side.

Divide $7$ by $7$ .

$x = 1$

Solve for x 3/4(x-1)+x=1

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