Solve for x -3=4x^2-x-3

$- 3 = 4 x^{2} - x - 3$

Step 1

Rewrite the equation as $4 x^{2} - x - 3 = - 3$ .

$4 x^{2} - x - 3 = - 3$

Step 2

Add $3$ to both sides of the equation.

$4 x^{2} - x - 3 + 3 = 0$

Step 3

Combine the opposite terms in $4 x^{2} - x - 3 + 3$ .

Add $- 3$ and $3$ .

$4 x^{2} - x + 0 = 0$

Add $4 x^{2} - x$ and $0$ .

$4 x^{2} - x = 0$

Step 4

Factor $x$ out of $4 x^{2} - x$ .

Factor $x$ out of $4 x^{2}$ .

$x (4 x) - x = 0$

Factor $x$ out of $- x$ .

$x (4 x) + x \cdot - 1 = 0$

Factor $x$ out of $x (4 x) + x \cdot - 1$ .

$x (4 x - 1) = 0$

Step 5

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$4 x - 1 = 0$

Step 6

Set $x$ equal to $0$ .

$x = 0$

Step 7

Set $4 x - 1$ equal to $0$ and solve for $x$ .

Set $4 x - 1$ equal to $0$ .

$4 x - 1 = 0$

Solve $4 x - 1 = 0$ for $x$ .

Add $1$ to both sides of the equation.

$4 x = 1$

Divide each term in $4 x = 1$ by $4$ and simplify.

Divide each term in $4 x = 1$ by $4$ .

$\frac{4 x}{4} = \frac{1}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{1}{4}$

Divide $x$ by $1$ .

$x = \frac{1}{4}$

Step 8

The final solution is all the values that make $x (4 x - 1) = 0$ true.

$x = 0, \frac{1}{4}$

Step 9

The result can be shown in multiple forms.

Exact Form:

$x = 0, \frac{1}{4}$

Decimal Form:

$x = 0, 0.25$

Solve for x -3=4x^2-x-3

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