Solve for x 3(4x-2x)=8

$3 (4 x - 2 x) = 8$

Step 1

Simplify.

Subtract $2 x$ from $4 x$ .

$3 (2 x) = 8$

Multiply $2$ by $3$ .

$6 x = 8$

Step 2

Divide each term in $6 x = 8$ by $3$ and simplify.

Divide each term in $6 x = 8$ by $3$ .

$\frac{6 x}{3} = \frac{8}{3}$

Simplify the left side.

Cancel the common factor of $6$ and $3$ .

Factor $3$ out of $6 x$ .

$\frac{3 (2 x)}{3} = \frac{8}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$\frac{3 (2 x)}{3 (1)} = \frac{8}{3}$

Cancel the common factor.

$\frac{3 (2 x)}{3 \cdot 1} = \frac{8}{3}$

Rewrite the expression.

$\frac{2 x}{1} = \frac{8}{3}$

Divide $2 x$ by $1$ .

$2 x = \frac{8}{3}$

Step 3

Divide each term in $2 x = \frac{8}{3}$ by $2$ and simplify.

Divide each term in $2 x = \frac{8}{3}$ by $2$ .

$\frac{2 x}{2} = \frac{\frac{8}{3}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{\frac{8}{3}}{2}$

Divide $x$ by $1$ .

$x = \frac{\frac{8}{3}}{2}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{8}{3} \cdot \frac{1}{2}$

Cancel the common factor of $2$ .

Factor $2$ out of $8$ .

$x = \frac{2 (4)}{3} \cdot \frac{1}{2}$

Cancel the common factor.

$x = \frac{2 \cdot 4}{3} \cdot \frac{1}{2}$

Rewrite the expression.

$x = \frac{4}{3}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{4}{3}$

Decimal Form:

$x = 1.\overline{3}$

Mixed Number Form:

$x = 1 \frac{1}{3}$

Solve for x 3(4x-2x)=8

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