Solve for x -3(4x+3)+4(6x+1)=43

$- 3 (4 x + 3) + 4 (6 x + 1) = 43$

Step 1

Simplify $- 3 (4 x + 3) + 4 (6 x + 1)$ .

Simplify each term.

Apply the distributive property.

$- 3 (4 x) - 3 \cdot 3 + 4 (6 x + 1) = 43$

Multiply $4$ by $- 3$ .

$- 12 x - 3 \cdot 3 + 4 (6 x + 1) = 43$

Multiply $- 3$ by $3$ .

$- 12 x - 9 + 4 (6 x + 1) = 43$

Apply the distributive property.

$- 12 x - 9 + 4 (6 x) + 4 \cdot 1 = 43$

Multiply $6$ by $4$ .

$- 12 x - 9 + 24 x + 4 \cdot 1 = 43$

Multiply $4$ by $1$ .

$- 12 x - 9 + 24 x + 4 = 43$

Simplify by adding terms.

Add $- 12 x$ and $24 x$ .

$12 x - 9 + 4 = 43$

Add $- 9$ and $4$ .

$12 x - 5 = 43$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$12 x = 43 + 5$

Add $43$ and $5$ .

$12 x = 48$

Step 3

Divide each term in $12 x = 48$ by $12$ and simplify.

Divide each term in $12 x = 48$ by $12$ .

$\frac{12 x}{12} = \frac{48}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 x}{12} = \frac{48}{12}$

Divide $x$ by $1$ .

$x = \frac{48}{12}$

Simplify the right side.

Divide $48$ by $12$ .

$x = 4$