Solve for x (3/5)^x=(27/125)

${(\frac{3}{5})}^{x} = (\frac{27}{125})$

Step 1

Create equivalent expressions in the equation that all have equal bases.

${(\frac{3}{5})}^{x} = {(\frac{3}{5})}^{3}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x = 3$